04e99c1e1b
### What changes were proposed in this pull request? remove python2.7 tests and test infra for 3.0+ ### Why are the changes needed? because python2.7 is finally going the way of the dodo. ### Does this PR introduce any user-facing change? newp. ### How was this patch tested? the build system will test this Closes #26330 from shaneknapp/remove-py27-tests. Lead-authored-by: shane knapp <incomplete@gmail.com> Co-authored-by: shane <incomplete@gmail.com> Signed-off-by: shane knapp <incomplete@gmail.com>
90 lines
2.7 KiB
Python
90 lines
2.7 KiB
Python
#
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# Licensed to the Apache Software Foundation (ASF) under one or more
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# contributor license agreements. See the NOTICE file distributed with
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# this work for additional information regarding copyright ownership.
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# The ASF licenses this file to You under the Apache License, Version 2.0
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# (the "License"); you may not use this file except in compliance with
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# the License. You may obtain a copy of the License at
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#
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# http://www.apache.org/licenses/LICENSE-2.0
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#
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# Unless required by applicable law or agreed to in writing, software
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# distributed under the License is distributed on an "AS IS" BASIS,
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# WITHOUT WARRANTIES OR CONDITIONS OF ANY KIND, either express or implied.
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# See the License for the specific language governing permissions and
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# limitations under the License.
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#
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import os
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import shutil
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import subprocess
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import sys
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subprocess_check_output = subprocess.check_output
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def exit_from_command_with_retcode(cmd, retcode):
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if retcode < 0:
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print("[error] running", ' '.join(cmd), "; process was terminated by signal", -retcode)
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else:
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print("[error] running", ' '.join(cmd), "; received return code", retcode)
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sys.exit(int(os.environ.get("CURRENT_BLOCK", 255)))
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def rm_r(path):
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"""
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Given an arbitrary path, properly remove it with the correct Python construct if it exists.
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From: http://stackoverflow.com/a/9559881
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"""
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if os.path.isdir(path):
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shutil.rmtree(path)
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elif os.path.exists(path):
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os.remove(path)
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def run_cmd(cmd, return_output=False):
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"""
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Given a command as a list of arguments will attempt to execute the command
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and, on failure, print an error message and exit.
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"""
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if not isinstance(cmd, list):
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cmd = cmd.split()
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try:
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if return_output:
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return subprocess_check_output(cmd).decode('utf-8')
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else:
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return subprocess.run(cmd, universal_newlines=True, check=True)
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except subprocess.CalledProcessError as e:
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exit_from_command_with_retcode(e.cmd, e.returncode)
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def is_exe(path):
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"""
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Check if a given path is an executable file.
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From: http://stackoverflow.com/a/377028
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"""
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return os.path.isfile(path) and os.access(path, os.X_OK)
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def which(program):
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"""
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Find and return the given program by its absolute path or 'None' if the program cannot be found.
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From: http://stackoverflow.com/a/377028
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"""
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fpath = os.path.split(program)[0]
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if fpath:
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if is_exe(program):
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return program
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else:
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for path in os.environ.get("PATH").split(os.pathsep):
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path = path.strip('"')
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exe_file = os.path.join(path, program)
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if is_exe(exe_file):
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return exe_file
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return None
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