4360c6f12a
### What changes were proposed in this pull request? add prompt information about current applicationId, current URL and master info when pyspark / sparkR starts. ### Why are the changes needed? The information printed when pyspark/sparkR starts does not prompt the basic information of current application, and it is not convenient when used pyspark/sparkR in dos. ### Does this PR introduce _any_ user-facing change? no ### How was this patch tested? manual test result shows below: ![pyspark new print](https://user-images.githubusercontent.com/52202080/98274268-2a663f00-1fce-11eb-88ce-964ce90b439e.png) ![sparkR](https://user-images.githubusercontent.com/52202080/98541235-1a01dd00-22ca-11eb-9304-09bcde87b05e.png) Closes #30266 from akiyamaneko/pyspark-hint-info. Authored-by: neko <echohlne@gmail.com> Signed-off-by: HyukjinKwon <gurwls223@apache.org>
76 lines
2.4 KiB
Python
76 lines
2.4 KiB
Python
#
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# Licensed to the Apache Software Foundation (ASF) under one or more
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# contributor license agreements. See the NOTICE file distributed with
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# this work for additional information regarding copyright ownership.
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# The ASF licenses this file to You under the Apache License, Version 2.0
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# (the "License"); you may not use this file except in compliance with
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# the License. You may obtain a copy of the License at
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#
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# http://www.apache.org/licenses/LICENSE-2.0
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#
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# Unless required by applicable law or agreed to in writing, software
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# distributed under the License is distributed on an "AS IS" BASIS,
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# WITHOUT WARRANTIES OR CONDITIONS OF ANY KIND, either express or implied.
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# See the License for the specific language governing permissions and
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# limitations under the License.
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#
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"""
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An interactive shell.
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This file is designed to be launched as a PYTHONSTARTUP script.
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"""
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import atexit
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import os
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import platform
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import warnings
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from pyspark.context import SparkContext
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from pyspark.sql import SparkSession
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if os.environ.get("SPARK_EXECUTOR_URI"):
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SparkContext.setSystemProperty("spark.executor.uri", os.environ["SPARK_EXECUTOR_URI"])
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SparkContext._ensure_initialized() # type: ignore
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try:
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spark = SparkSession._create_shell_session() # type: ignore
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except Exception:
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import sys
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import traceback
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warnings.warn("Failed to initialize Spark session.")
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traceback.print_exc(file=sys.stderr)
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sys.exit(1)
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sc = spark.sparkContext
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sql = spark.sql
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atexit.register(lambda: sc.stop())
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# for compatibility
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sqlContext = spark._wrapped
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sqlCtx = sqlContext
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print(r"""Welcome to
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____ __
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/ __/__ ___ _____/ /__
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_\ \/ _ \/ _ `/ __/ '_/
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/__ / .__/\_,_/_/ /_/\_\ version %s
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/_/
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""" % sc.version)
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print("Using Python version %s (%s, %s)" % (
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platform.python_version(),
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platform.python_build()[0],
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platform.python_build()[1]))
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print("Spark context Web UI available at %s" % (sc.uiWebUrl))
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print("Spark context available as 'sc' (master = %s, app id = %s)." % (sc.master, sc.applicationId))
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print("SparkSession available as 'spark'.")
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# The ./bin/pyspark script stores the old PYTHONSTARTUP value in OLD_PYTHONSTARTUP,
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# which allows us to execute the user's PYTHONSTARTUP file:
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_pythonstartup = os.environ.get('OLD_PYTHONSTARTUP')
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if _pythonstartup and os.path.isfile(_pythonstartup):
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with open(_pythonstartup) as f:
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code = compile(f.read(), _pythonstartup, 'exec')
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exec(code)
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