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## What changes were proposed in this pull request? Replace sortBy() with top() to calculate the top N frequent words as dictionary. ## How was this patch tested? existing unit tests. The terms with same TF would be sorted in descending order. The test would fail if hardcode the terms with same TF the dictionary like "c", "d"... Author: fwang1 <desperado.wf@gmail.com> Closes #12265 from lionelfeng/master. |
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